#include <bits/stdc++.h>
using namespace std;
#define ll long long
const ll nx=2e5+5;
ll n, m, q, l, r, s, t, x; // t=currenttime
vector<pair<ll, ll>> ins;
map<ll, pair<ll, ll>> mp; // key = r, value = {l, last_value}
void split(ll x) // split x, x+1 ออกเป็นสองช่วง
{
if (!x) return; // x = 0
auto itr=mp.lower_bound(x); // หาช่วงที่คลุม x
int oldl=itr->second.first, oldr=itr->first, oldvalue=itr->second.second;
if (oldr==x) return; // rightmost of the range is indeed x
mp[x]={oldl, itr->second.second-(itr->first-x)}; // new range with the rightmost position as x
itr->second.first=x+1; // แก้ช่วงเดิม (ขอบซ้ายของช่วงเดิม)
}
int main()
{
cin.tie(NULL)->sync_with_stdio(false);
cin>>n>>m>>q;
mp[n]={1, -1e18};
for (int i=1; i<=m; i++)
{
cin>>l>>r;
split(l-1); // split l-1 and l
split(r);
// ไล่ทุกช่วงที่อยู่ใน range (l, r)
for (auto itr=mp.lower_bound(l); itr!=mp.end()&&itr->first<=r; itr=mp.erase(itr)) // mp.erase() return the next iterator
{
// itr แต่ละบล้อคที่จะลบทิ้ง
ll curl=itr->second.first, curr=itr->first, curend=itr->second.second;
ll sz=curr-curl+1;
t+=sz; // t=ending time of current block we're considering
ins.push_back({t-curend, sz}); // {value, amount that we got}
} // total running time <= amount time we add range into map (3*m)
mp[r]={l, t}; // add new range
}
sort(ins.begin(), ins.end());
for (int i=0; i<ins.size(); i++) if (ins[i].first>=1e18) ins[i].second=0;
for (int i=(int)ins.size()-2; i>=0; i--) ins[i].second+=ins[i+1].second;
for (int i=1; i<=q; i++)
{
cin>>x;
// หา sum of ins[].second that ins[].first>x
auto itr=upper_bound(ins.begin(), ins.end(), make_pair(x, LLONG_MAX));
cout<<itr->second<<' ';
}
}
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