제출 #1322487

#제출 시각아이디문제언어결과실행 시간메모리
1322487chithanhnguyenHedgehog Daniyar and Algorithms (IZhO19_sortbooks)C++20
100 / 100
856 ms105428 KiB
/* Author: Nguyen Chi Thanh - High School for the Gifted - VNU.HCM (i2528) */ #include <bits/stdc++.h> using namespace std; #define int long long #define ull unsigned long long #define ld long double #define pii pair<int, int> #define fi first #define se second #define __builtin_popcount __builtin_popcountll #define all(x) (x).begin(), (x).end() #define BIT(x, i) (((x) >> (i)) & 1) #define MASK(x) ((1ll << (x))) #define debug(a, l, r) for (int _i = (l); _i <= (r); ++_i) cout << (a)[_i] << ' '; cout << '\n'; const int INF = 1e18 + 5; struct SegmentTree{ int n; vector<int> st; SegmentTree() { } SegmentTree(int n) : n(n) { st.resize(4 * n + 5, 0ll); } void update(int id, int l, int r, int pos, int val) { if (l > pos || r < pos) return; if (l == r) { st[id] = max(st[id], val); return; } int mid = (l + r) >> 1; update(id << 1, l, mid, pos, val); update((id << 1) | 1, mid + 1, r, pos, val); st[id] = max(st[id << 1], st[(id << 1) | 1]); } int get(int id, int l, int r, int u, int v) { if (l > v || r < u) return -INF; if (l >= u && r <= v) return st[id]; int mid = (l + r) >> 1; int get1 = get(id << 1, l, mid, u, v); int get2 = get((id << 1) | 1, mid + 1, r, u, v); return max(get1, get2); } void update(int l, int r) { update(1, 1, n, l, r); } int get(int l, int r) { return get(1, 1, n, l, r); } }; struct Query { int l, k, id; }; const int MAXN = 1e6 + 6; int n, q, a[MAXN], l[MAXN]; vector<Query> queries[MAXN]; void init() { cin >> n >> q; for (int i = 1; i <= n; ++i) cin >> a[i]; for (int i = 1; i <= q; ++i) { int l, r, k; cin >> l >> r >> k; queries[r].push_back({l, k, i}); } vector<int> stk; // Vector-based stack for (int i = 1; i <= n; ++i) { while (!stk.empty() && a[stk.back()] <= a[i]) stk.pop_back(); l[i] = (stk.empty() ? 0 : stk.back()); stk.push_back(i); } } bitset<MAXN> ans; void solve() { SegmentTree seg(n + 5); for (int r = 1; r <= n; ++r) { if (l[r] != 0) seg.update(l[r], a[r] + a[l[r]]); for (auto &qry : queries[r]) { int l = qry.l, k = qry.k, id = qry.id; int mxval = seg.get(l, r); ans[id] = (mxval <= k); } } for (int i = 1; i <= q; ++i) cout << ans[i] << '\n'; } signed main() { #ifdef NCTHANH freopen("input.txt", "r", stdin); freopen("output.txt", "w", stdout); #endif ios_base::sync_with_stdio(0); cin.tie(nullptr); cout.tie(nullptr); init(); solve(); return 0; }
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