Submission #1302220

#TimeUsernameProblemLanguageResultExecution timeMemory
1302220vlomaczkSoccer (JOI17_soccer)C++20
0 / 100
309 ms24584 KiB
#include <bits/stdc++.h> #include <ext/pb_ds/assoc_container.hpp> #include <ext/pb_ds/tree_policy.hpp> typedef long long ll; using namespace __gnu_pbds; using namespace std; template <typename T> using ordered_set = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>; int main() { ios_base::sync_with_stdio(0); cin.tie(0); cout.tie(0); ll H,W; cin >> H >> W; ll A,B,C; cin >> A >> B >> C; ll n; cin >> n; vector<int> row(n), col(n); for(ll i=0; i<n; ++i) { cin >> row[i] >> col[i]; } ll inf = 1e18; vector<vector<ll>> closest(H+1,vector<ll>(W+1, 1e6)); queue<pair<int, int>> Q; for(int i=0; i<n-1; ++i) { Q.push({row[i], col[i]}); closest[row[i]][col[i]] = 0; } auto chk = [&](int r, int c, int d) { if(r < 0 || r > H || c < 0 || c > W) return; if(closest[r][c] < 1e6) return; closest[r][c] = d; Q.push({r,c}); }; while(Q.size()) { auto[r,c] = Q.front(); Q.pop(); chk(r+1,c,closest[r][c]+1); chk(r-1,c,closest[r][c]+1); chk(r,c+1,closest[r][c]+1); chk(r,c-1,closest[r][c]+1); } vector<vector<vector<ll>>> dist(H+1, vector<vector<ll>>(W+1, vector<ll>(3, inf))); priority_queue<pair<int, pair<pair<int, int>, int>>> pq; auto check = [&](int r, int c, int m, int d) { if(r < 0 || r > H || c < 0 || c > W) return; if(dist[r][c][m] > d) { dist[r][c][m] = d; pq.push({-d, {{r,c},m}}); } }; dist[row[0]][col[0]][0] = 0; pq.push({0, {{row[0], col[0]}, 0}}); while(pq.size()) { auto[dv, stat] = pq.top(); pq.pop(); dv*=-1; auto[pos, mode] = stat; auto[r,c] = pos; if(dist[r][c][mode] != dv) continue; if(mode==0) { check(r+1, c, 0, dv+C); check(r-1, c, 0, dv+C); check(r, c+1, 0, dv+C); check(r, c-1, 0, dv+C); check(r, c, 1, dv+B); check(r, c, 2, dv+B); } else if(mode==1) { check(r+1, c, 1, dv+A); check(r-1, c, 1, dv+A); } else { check(r, c+1, 2, dv+A); check(r, c-1, 2, dv+A); } if(mode) check(r,c,0,dv + C*closest[r][c]); } int r = row[n-1]; int c = col[n-1]; cout << min(dist[r][c][0], min(dist[r][c][1], dist[r][c][2])) << "\n"; return 0; }
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