제출 #1303685

#제출 시각아이디문제언어결과실행 시간메모리
1303685NonozeXylophone (JOI18_xylophone)C++20
100 / 100
260 ms98572 KiB
#include "xylophone.h" /* * Author: Nonoze * Created: Wednesday 17/12/2025 */ #include <bits/stdc++.h> using namespace std; #ifndef DEBUG #define dbg(...) #endif // #define cout cerr << "OUT: " #define endl '\n' #define endlfl '\n' << flush #define quit(x) return (void)(cout << x << endl) template<typename T> void read(T& x) { cin >> x; } template<typename T1, typename T2> void read(pair<T1, T2>& p) { read(p.first), read(p.second); } template<typename T> void read(vector<T>& v) { for (auto& x : v) read(x); } template<typename T1, typename T2> void read(T1& x, T2& y) { read(x), read(y); } template<typename T1, typename T2, typename T3> void read(T1& x, T2& y, T3& z) { read(x), read(y), read(z); } template<typename T1, typename T2, typename T3, typename T4> void read(T1& x, T2& y, T3& z, T4& zz) { read(x), read(y), read(z), read(zz); } template<typename T> void print(vector<T>& v) { for (auto& x : v) cout << x << ' '; cout << endl; } #define sz(x) (int)(x.size()) #define all(x) (x).begin(), (x).end() #define rall(x) (x).rbegin(), (x).rend() #define make_unique(v) sort(all(v)), v.erase(unique(all(v)), (v).end()) #define pb push_back #define mp(a, b) make_pair(a, b) #define fi first #define se second #define cmin(a, b) a = min(a, b) #define cmax(a, b) a = max(a, b) #define YES cout << "YES" << endl #define NO cout << "NO" << endl #define QYES quit("YES") #define QNO quit("NO") #define double long double const int inf = numeric_limits<int>::max() / 4; const int MOD = 1e9+7, LOG=20; static int A[5001]; vector<vector<int>> sol; int que(int s, int t) { int x=min(s, t), y=max(s, t); if (sol[x][y]!=-1) return sol[x][y]; return sol[x][y]=query(x, y); } vector<int> calc(int prec, int cur, int n) { int pos=2; vector<bool> used(n+1, false); used[prec]=used[cur]=true; vector<int> res={prec, cur}; A[1]=prec, A[2]=cur; while (pos!=n) { pos++; int val=que(pos, pos-2); if (prec<cur) { if (val==cur-prec) { val=que(pos, pos-1); A[pos]=cur-val; cur=A[pos], prec=A[pos-1]; } else if (que(pos, pos-1)==val) { A[pos]=cur-val; cur=A[pos], prec=A[pos-1]; } else { A[pos]=prec+val; cur=A[pos], prec=A[pos-1]; } } else { if (val==prec-cur) { val=que(pos, pos-1); A[pos]=cur+val; cur=A[pos], prec=A[pos-1]; } else if (que(pos, pos-1)==val) { A[pos]=cur+val; cur=A[pos], prec=A[pos-1]; } else { A[pos]=prec-val; prec=cur, cur= cur=A[pos], prec=A[pos-1]; } } if (cur<1 || cur>n || used[cur] || (cur==1 && used[n])) return {}; used[cur] = true; res.pb(cur); } return res; } void solve(int N) { sol.resize(N+1, vector<int>(N+1, -1)); vector<vector<int>> vals; for (int i=1; i<=N; i++) { int prec=i, diff=que(1, 2); if (prec+diff<=N) vals.pb(calc(prec, prec+diff, N)); if (!vals.empty() && vals.back().empty()) vals.pop_back(); if (prec-diff>=1 && diff!=N-1) vals.pb(calc(prec, prec-diff, N)); if (!vals.empty() && vals.back().empty()) vals.pop_back(); } assert(sz(vals)==1); for (int i=1; i<=N; i++) { answer(i, vals[0][i-1]); } }
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