// #pragma optimize ("g",on) // #pragma GCC optimize ("inline") // #pragma GCC optimize ("Ofast") // #pragma GCC optimize ("unroll-loops") // #pragma GCC optimize ("03") #include <bits/stdc++.h> #define SS ios_base::sync_with_stdio(0);cin.tie(nullptr);cout.tie(nullptr); // #define int long long #define all(v) v.begin(),v.end() using namespace std; // mt19937 rnd(chrono::steady_clock::now().time_since_epoch().count()); const int N = 1e4 + 1, MX = 40, inf = 1e18; void solve(){ int n, vmx, vf; cin >> n >> vmx >> vf; pair<char, int> p[n + 1]; p[0].second = 0; int cm = 0, cp = 0, mx = 0; for(int i = 1; i <= n; i++){ cin >> p[i].first >> p[i].second; } int rest = 0, resv = 0; for(int vs = 0; vs <= vmx; vs++){ int cur = vs; for(int i = 2; i <= n; i++){ cur = max(0, cur - (p[i].first == '-')); cur = min(vmx, cur + (p[i].first == '+')); } if(cur == vf){ cout << "infinty"; return; } } for(int t = 5000; t >= 1; t--){ int vs = vmx; for(int i = 2; i <= n; i++){ if(p[i].second - p[i - 1].second <= t){ vs = max(0, vs - (p[i].first == '-')); vs = min(vmx, vs + (p[i].first == '+')); } } if(vs < vf) continue; if(vs >= vf){ cout << t << ' ' << vmx - (vs - vf) << '\n'; return; } } } signed main(){ SS // freopen("trains.in", "r", stdin); // freopen("trains.out", "w", stdout); int t = 1; // cin >> t; while(t--){ solve(); } }

mp3player.cpp:14:39: warning: overflow in conversion from 'double' to 'int' changes value from '1.0e+18' to '2147483647' [-Woverflow]
   14 | const int N = 1e4 + 1, MX = 40, inf = 1e18;
      |                                       ^~~~