#include <iostream>
#include <string>
using namespace std;
typedef long long llong;
int main()
{
string s;
cin >> s;
int n = s.size();
llong l = n / 2;
llong r = (n + 1) / 2;
llong sum = l * (l - 1) / 2LL + r * (r - 1) / 2LL;
cout << sum / 2;
if(sum % 2 == 1)
{
cout << ".5" << endl;
}
else
{
cout << endl;
}
return 0;
}
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