| # | Time | Username | Problem | Language | Result | Execution time | Memory |
|---|---|---|---|---|---|---|---|
| 448548 | rainboy | Rima (COCI17_rima) | C11 | 1094 ms | 65556 KiB |
This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#define N 500000
#define L 3000000
int max(int a, int b) { return a > b ? a : b; }
unsigned int X = 12345;
int rand_() {
return (X *= 3) >> 1;
}
char *ss[N * 2];
int compare(int i, int j) {
int c = strcmp(ss[i], ss[j]);
return c == 0 ? i - j : c;
}
void sort(int *ii, int l, int r) {
while (l < r) {
int i = l, j = l, k = r, i_ = ii[l + rand_() % (r - l)], tmp;
while (j < k) {
int c = compare(ii[j], i_);
if (c == 0)
j++;
else if (c < 0) {
tmp = ii[i], ii[i] = ii[j], ii[j] = tmp;
i++, j++;
} else {
k--;
tmp = ii[j], ii[j] = ii[k], ii[k] = tmp;
}
}
sort(ii, l, i);
l = k;
}
}
int *ej[N], eo[N];
void append(int i, int j) {
int o = eo[i]++;
if (o >= 2 && (o & o - 1) == 0)
ej[i] = (int *) realloc(ej[i], o * 2 * sizeof *ej[i]);
ej[i][o] = j;
}
int dp[N];
void dfs(int i) {
int o;
for (o = eo[i]; o--; ) {
int j = ej[i][o];
dfs(j);
dp[i] = max(dp[i], dp[j] - 1);
}
dp[i] += 1 + eo[i];
}
int main() {
static int ii[N * 2];
static char root[N];
int n, i, j, ans;
scanf("%d", &n);
for (i = 0; i < n; i++) {
static char s[L + 1];
int l, h1, h2;
char tmp;
scanf("%s", s), l = strlen(s);
for (h1 = 0, h2 = l - 1; h1 < h2; h1++, h2--)
tmp = s[h1], s[h1] = s[h2], s[h2] = tmp;
ss[i] = strdup(s);
s[l - 1] = 0;
ss[n + i] = strdup(s);
}
for (i = 0; i < n * 2; i++)
ii[i] = i;
sort(ii, 0, n * 2);
for (i = 0; i < n; i++)
ej[i] = (int *) malloc(2 * sizeof *ej[i]);
for (i = 0, j = 0; j < n * 2; i = j) {
j = i + 1;
if (ii[i] >= n)
root[ii[i] - n] = 1;
while (j < n * 2 && strcmp(ss[ii[i]], ss[ii[j]]) == 0) {
if (ii[i] < n)
append(ii[i], ii[j] - n);
else
root[ii[j] - n] = 1;
j++;
}
}
for (i = 0; i < n; i++)
if (root[i])
dfs(i);
ans = 0;
for (i = 0, j = 0; j < n * 2; i = j) {
int mx1, mx2;
j = i;
if (ii[j] < n)
j++;
mx1 = mx2 = 0;
while (j < n * 2 && strcmp(ss[ii[i]], ss[ii[j]]) == 0) {
int j_ = ii[j++] - n;
if (mx1 < dp[j_] - 1)
mx2 = mx1, mx1 = dp[j_] - 1;
else if (mx2 < dp[j_] - 1)
mx2 = dp[j_] - 1;
}
ans = max(ans, j - i + mx1 + mx2);
}
printf("%d\n", ans);
return 0;
}
Compilation message (stderr)
| # | Verdict | Execution time | Memory | Grader output |
|---|---|---|---|---|
| Fetching results... | ||||
